2(-10a-4)+11(a+2)=4-4a

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Solution for 2(-10a-4)+11(a+2)=4-4a equation: 



2(-10a-4)+11(a+2)=4-4a

We move all terms to the left:

2(-10a-4)+11(a+2)-(4-4a)=0

We add all the numbers together, and all the variables

2(-10a-4)+11(a+2)-(-4a+4)=0

We multiply parentheses

-20a+11a-(-4a+4)-8+22=0

We get rid of parentheses

-20a+11a+4a-4-8+22=0

We add all the numbers together, and all the variables

-5a+10=0

We move all terms containing a to the left, all other terms to the right

-5a=-10

a=-10/-5

a=+2

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