2((3y+29)/4)-y=7

Solution for 2((3y+29)/4)-y=7 equation:

2((3y+29)/4)-y=7

We move all terms to the left:

2((3y+29)/4)-y-(7)=0

We add all the numbers together, and all the variables

-1y+2((3y+29)/4)-7=0

We multiply all the terms by the denominator


-1y*4)+2((3y+29)-7*4)=0

We add all the numbers together, and all the variables

-1y*4)+2((3y+29)=0

Wy multiply elements

-4y^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-8}=0$