1y-3=1y+(-3)

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Solution for 1y-3=1y+(-3) equation: 



1y-3=1y+(-3)

We move all terms to the left:

1y-3-(1y+(-3))=0

We add all the numbers together, and all the variables

y-(1y+(-3))-3=0



We calculate terms in parentheses: -(1y+(-3)), so:

1y+(-3)

We add all the numbers together, and all the variables

y-3

Back to the equation:

-(y-3)



We get rid of parentheses

y-y+3-3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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