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1y+2/3y=45
We move all terms to the left:
1y+2/3y-(45)=0
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
y+2/3y-45=0
We multiply all the terms by the denominator
y*3y-45*3y+2=0
Wy multiply elements
3y^2-135y+2=0
a = 3; b = -135; c = +2;
Δ = b2-4ac
Δ = -1352-4·3·2
Δ = 18201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-135)-\sqrt{18201}}{2*3}=\frac{135-\sqrt{18201}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-135)+\sqrt{18201}}{2*3}=\frac{135+\sqrt{18201}}{6} $
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