1y+(2y-10)+4y=123

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Solution for 1y+(2y-10)+4y=123 equation: 



1y+(2y-10)+4y=123

We move all terms to the left:

1y+(2y-10)+4y-(123)=0

We add all the numbers together, and all the variables

5y+(2y-10)-123=0

We get rid of parentheses

5y+2y-10-123=0

We add all the numbers together, and all the variables

7y-133=0

We move all terms containing y to the left, all other terms to the right

7y=133

y=133/7

y=19

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