1x=x+8x2+4x-x+7x

Solution for 1x=x+8x2+4x-x+7x equation:

1x=x+8x^2+4x-x+7x

We move all terms to the left:

1x-(x+8x^2+4x-x+7x)=0

We add all the numbers together, and all the variables

-(x+8x^2+4x-x+7x)+x=0

We get rid of parentheses

-8x^2-x-4x+x-7x+x=0

We add all the numbers together, and all the variables

-8x^2-10x=0

a = -8; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-8)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-8}=\frac{20}{-16}
=-1+1/4
$