1x2+15x-25=-50

Solution for 1x2+15x-25=-50 equation:

1x^2+15x-25=-50

We move all terms to the left:

1x^2+15x-25-(-50)=0

We add all the numbers together, and all the variables

x^2+15x+25=0

a = 1; b = 15; c = +25;
Δ = b2-4ac
Δ = 152-4·1·25
Δ = 125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{125}=\sqrt{25*5}=\sqrt{25}*\sqrt{5}=5\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{5}}{2*1}=\frac{-15-5\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{5}}{2*1}=\frac{-15+5\sqrt{5}}{2}
$