If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
((1*x)/1)*x = y // - y
((1*x)/1)*x-y = 0
x*x-y = 0
1*x^2 = y // : 1
x^2 = y
x^2 = y // ^ 1/2
abs(x) = y^(1/2)
x = y^(1/2) or x = -y^(1/2)
x in { y^(1/2), -y^(1/2) }
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