1x+6=2(x+3)

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Solution for 1x+6=2(x+3) equation: 



1x+6=2(x+3)

We move all terms to the left:

1x+6-(2(x+3))=0

We add all the numbers together, and all the variables

x-(2(x+3))+6=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

x-2x-6+6=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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