1x+5(x+1)=4(2x-2)+11x

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Solution for 1x+5(x+1)=4(2x-2)+11x equation: 



1x+5(x+1)=4(2x-2)+11x

We move all terms to the left:

1x+5(x+1)-(4(2x-2)+11x)=0

We add all the numbers together, and all the variables

x+5(x+1)-(4(2x-2)+11x)=0

We multiply parentheses

x+5x-(4(2x-2)+11x)+5=0



We calculate terms in parentheses: -(4(2x-2)+11x), so:

4(2x-2)+11x

We add all the numbers together, and all the variables

11x+4(2x-2)

We multiply parentheses

11x+8x-8

We add all the numbers together, and all the variables

19x-8

Back to the equation:

-(19x-8)



We add all the numbers together, and all the variables

6x-(19x-8)+5=0

We get rid of parentheses

6x-19x+8+5=0

We add all the numbers together, and all the variables

-13x+13=0

We move all terms containing x to the left, all other terms to the right

-13x=-13

x=-13/-13

x=1

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