1x+3=2(x+2)+5

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Solution for 1x+3=2(x+2)+5 equation: 



1x+3=2(x+2)+5

We move all terms to the left:

1x+3-(2(x+2)+5)=0

We add all the numbers together, and all the variables

x-(2(x+2)+5)+3=0



We calculate terms in parentheses: -(2(x+2)+5), so:

2(x+2)+5

We multiply parentheses

2x+4+5

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We get rid of parentheses

x-2x-9+3=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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