1x+3(92-2x)=161

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Solution for 1x+3(92-2x)=161 equation: 



1x+3(92-2x)=161

We move all terms to the left:

1x+3(92-2x)-(161)=0

We add all the numbers together, and all the variables

1x+3(-2x+92)-161=0

We add all the numbers together, and all the variables

x+3(-2x+92)-161=0

We multiply parentheses

x-6x+276-161=0

We add all the numbers together, and all the variables

-5x+115=0

We move all terms containing x to the left, all other terms to the right

-5x=-115

x=-115/-5

x=+23

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