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1x+25=x2+15
We move all terms to the left:
1x+25-(x2+15)=0
We add all the numbers together, and all the variables
-(+x^2+15)+1x+25=0
We add all the numbers together, and all the variables
-(+x^2+15)+x+25=0
We get rid of parentheses
-x^2+x-15+25=0
We add all the numbers together, and all the variables
-1x^2+x+10=0
a = -1; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-1)·10
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{41}}{2*-1}=\frac{-1-\sqrt{41}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{41}}{2*-1}=\frac{-1+\sqrt{41}}{-2} $
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