1x+1(1+1x)+1(1x+1)=200

Solution for 1x+1(1+1x)+1(1x+1)=200 equation:

Simplifying
1x + 1(1 + 1x) + 1(1x + 1) = 200
1x + (1 * 1 + 1x * 1) + 1(1x + 1) = 200
1x + (1 + 1x) + 1(1x + 1) = 200

Reorder the terms:
1x + 1 + 1x + 1(1 + 1x) = 200
1x + 1 + 1x + (1 * 1 + 1x * 1) = 200
1x + 1 + 1x + (1 + 1x) = 200

Reorder the terms:
1 + 1 + 1x + 1x + 1x = 200

Combine like terms: 1 + 1 = 2
2 + 1x + 1x + 1x = 200

Combine like terms: 1x + 1x = 2x
2 + 2x + 1x = 200

Combine like terms: 2x + 1x = 3x
2 + 3x = 200

Solving
2 + 3x = 200

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3x = 200 + -2

Combine like terms: 2 + -2 = 0
0 + 3x = 200 + -2
3x = 200 + -2

Combine like terms: 200 + -2 = 198
3x = 198

Divide each side by '3'.
x = 66

Simplifying
x = 66