1x+(x+1)+(x+2)=228

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Solution for 1x+(x+1)+(x+2)=228 equation:


Simplifying
1x + (x + 1) + (x + 2) = 228

Reorder the terms:
1x + (1 + x) + (x + 2) = 228

Remove parenthesis around (1 + x)
1x + 1 + x + (x + 2) = 228

Reorder the terms:
1x + 1 + x + (2 + x) = 228

Remove parenthesis around (2 + x)
1x + 1 + x + 2 + x = 228

Reorder the terms:
1 + 2 + 1x + x + x = 228

Combine like terms: 1 + 2 = 3
3 + 1x + x + x = 228

Combine like terms: 1x + x = 2x
3 + 2x + x = 228

Combine like terms: 2x + x = 3x
3 + 3x = 228

Solving
3 + 3x = 228

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 228 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 228 + -3
3x = 228 + -3

Combine like terms: 228 + -3 = 225
3x = 225

Divide each side by '3'.
x = 75

Simplifying
x = 75

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