1x+(2.5x-2000)+(0.20x+1000)=(1.5x-1000)+(2x-1500)+(0.25x+1400)

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Solution for 1x+(2.5x-2000)+(0.20x+1000)=(1.5x-1000)+(2x-1500)+(0.25x+1400) equation: 



1x+(2.5x-2000)+(0.20x+1000)=(1.5x-1000)+(2x-1500)+(0.25x+1400)

We move all terms to the left:

1x+(2.5x-2000)+(0.20x+1000)-((1.5x-1000)+(2x-1500)+(0.25x+1400))=0

We add all the numbers together, and all the variables

x+(2.5x-2000)+(0.20x+1000)-((1.5x-1000)+(2x-1500)+(0.25x+1400))=0

We get rid of parentheses

x+2.5x+0.20x-((1.5x-1000)+(2x-1500)+(0.25x+1400))-2000+1000=0



We calculate terms in parentheses: -((1.5x-1000)+(2x-1500)+(0.25x+1400)), so:

(1.5x-1000)+(2x-1500)+(0.25x+1400)

We get rid of parentheses

1.5x+2x+0.25x-1000-1500+1400

We add all the numbers together, and all the variables

3.75x-1100

Back to the equation:

-(3.75x-1100)



We add all the numbers together, and all the variables

3.7x-(3.75x-1100)-1000=0

We get rid of parentheses

3.7x-3.75x+1100-1000=0

We add all the numbers together, and all the variables

-0.05x+100=0

We move all terms containing x to the left, all other terms to the right

-0.05x=-100

x=-100/-0.05

x=+2000

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