1x*2,5x=134

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Solution for 1x*2,5x=134 equation:



1x*2.5x=134
We move all terms to the left:
1x*2.5x-(134)=0
Wy multiply elements
2x^2-134=0
a = 2; b = 0; c = -134;
Δ = b2-4ac
Δ = 02-4·2·(-134)
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{67}}{2*2}=\frac{0-4\sqrt{67}}{4} =-\frac{4\sqrt{67}}{4} =-\sqrt{67} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{67}}{2*2}=\frac{0+4\sqrt{67}}{4} =\frac{4\sqrt{67}}{4} =\sqrt{67} $

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