1r-1(3r-1)=3(4r+5)

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Solution for 1r-1(3r-1)=3(4r+5) equation: 



1r-1(3r-1)=3(4r+5)

We move all terms to the left:

1r-1(3r-1)-(3(4r+5))=0

We add all the numbers together, and all the variables

r-1(3r-1)-(3(4r+5))=0



We calculate terms in parentheses: -(3(4r+5)), so:

3(4r+5)

We multiply parentheses

12r+15

Back to the equation:

-(12r+15)



We get rid of parentheses

r-1(3r-1)-12r-15=0

We add all the numbers together, and all the variables

-11r-1(3r-1)-15=0

We move all terms containing r to the left, all other terms to the right

-11r-1(3r-1)=15

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