1n/3+(n-2)/5=6

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Solution for 1n/3+(n-2)/5=6 equation: 


n in (-oo:+oo)

(n-2)/5+(1*n)/3 = 6 // - 6

(n-2)/5+(1*n)/3-6 = 0

(n-2)/5+n/3-6 = 0

(3*(n-2))/(3*5)+(5*n)/(3*5)+(-6*3*5)/(3*5) = 0

3*(n-2)+5*n-6*3*5 = 0

8*n-90-6 = 0

8*n-96 = 0

(8*n-96)/(3*5) = 0

(8*n-96)/(3*5) = 0 // * 3*5

8*n-96 = 0

8*n-96 = 0 // + 96

8*n = 96 // : 8

n = 96/8

n = 12

n = 12

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