1n+4(m+3)=17

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Solution for 1n+4(m+3)=17 equation:


Simplifying
1n + 4(m + 3) = 17

Reorder the terms:
1n + 4(3 + m) = 17
1n + (3 * 4 + m * 4) = 17
1n + (12 + 4m) = 17

Reorder the terms:
12 + 4m + 1n = 17

Solving
12 + 4m + 1n = 17

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 4m + -12 + 1n = 17 + -12

Reorder the terms:
12 + -12 + 4m + 1n = 17 + -12

Combine like terms: 12 + -12 = 0
0 + 4m + 1n = 17 + -12
4m + 1n = 17 + -12

Combine like terms: 17 + -12 = 5
4m + 1n = 5

Add '-1n' to each side of the equation.
4m + 1n + -1n = 5 + -1n

Combine like terms: 1n + -1n = 0
4m + 0 = 5 + -1n
4m = 5 + -1n

Divide each side by '4'.
m = 1.25 + -0.25n

Simplifying
m = 1.25 + -0.25n

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