1n+2(n-1)+3(n-2)=

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Solution for 1n+2(n-1)+3(n-2)= equation:


Simplifying
1n + 2(n + -1) + 3(n + -2) = 0

Reorder the terms:
1n + 2(-1 + n) + 3(n + -2) = 0
1n + (-1 * 2 + n * 2) + 3(n + -2) = 0
1n + (-2 + 2n) + 3(n + -2) = 0

Reorder the terms:
1n + -2 + 2n + 3(-2 + n) = 0
1n + -2 + 2n + (-2 * 3 + n * 3) = 0
1n + -2 + 2n + (-6 + 3n) = 0

Reorder the terms:
-2 + -6 + 1n + 2n + 3n = 0

Combine like terms: -2 + -6 = -8
-8 + 1n + 2n + 3n = 0

Combine like terms: 1n + 2n = 3n
-8 + 3n + 3n = 0

Combine like terms: 3n + 3n = 6n
-8 + 6n = 0

Solving
-8 + 6n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 6n = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 6n = 0 + 8
6n = 0 + 8

Combine like terms: 0 + 8 = 8
6n = 8

Divide each side by '6'.
n = 1.333333333

Simplifying
n = 1.333333333

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