1m=-(4+m)+2

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Solution for 1m=-(4+m)+2 equation: 



1m=-(4+m)+2

We move all terms to the left:

1m-(-(4+m)+2)=0

We add all the numbers together, and all the variables

1m-(-(m+4)+2)=0

We add all the numbers together, and all the variables

m-(-(m+4)+2)=0



We calculate terms in parentheses: -(-(m+4)+2), so:

-(m+4)+2

We get rid of parentheses

-m-4+2

We add all the numbers together, and all the variables

-1m-2

Back to the equation:

-(-1m-2)



We get rid of parentheses

m+1m+2=0

We add all the numbers together, and all the variables

2m+2=0

We move all terms containing m to the left, all other terms to the right

2m=-2

m=-2/2

m=-1

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