1c=8/c+2

Solution for 1c=8/c+2 equation:

1c=8/c+2

We move all terms to the left:

1c-(8/c+2)=0


Domain of the equation: c+2)!=0

c∈R


We add all the numbers together, and all the variables

c-(8/c+2)=0

We get rid of parentheses

c-8/c-2=0

We multiply all the terms by the denominator


c*c-2*c-8=0

We add all the numbers together, and all the variables

-2c+c*c-8=0

Wy multiply elements

c^2-2c-8=0

a = 1; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·1·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*1}=\frac{-4}{2}
=-2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*1}=\frac{8}{2}
=4
$