1c+(c+2)+(c+4)=27

Solution for 1c+(c+2)+(c+4)=27 equation:

Simplifying
1c + (c + 2) + (c + 4) = 27

Reorder the terms:
1c + (2 + c) + (c + 4) = 27

Remove parenthesis around (2 + c)
1c + 2 + c + (c + 4) = 27

Reorder the terms:
1c + 2 + c + (4 + c) = 27

Remove parenthesis around (4 + c)
1c + 2 + c + 4 + c = 27

Reorder the terms:
2 + 4 + 1c + c + c = 27

Combine like terms: 2 + 4 = 6
6 + 1c + c + c = 27

Combine like terms: 1c + c = 2c
6 + 2c + c = 27

Combine like terms: 2c + c = 3c
6 + 3c = 27

Solving
6 + 3c = 27

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3c = 27 + -6

Combine like terms: 6 + -6 = 0
0 + 3c = 27 + -6
3c = 27 + -6

Combine like terms: 27 + -6 = 21
3c = 21

Divide each side by '3'.
c = 7

Simplifying
c = 7