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1a/a2=11
We move all terms to the left:
1a/a2-(11)=0
Domain of the equation: a2!=0We multiply all the terms by the denominator
a^2!=0/
a^2!=√0
a!=0
a∈R
1a-11*a2=0
We add all the numbers together, and all the variables
-11a^2+a=0
a = -11; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-11)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-11}=\frac{-2}{-22} =1/11 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-11}=\frac{0}{-22} =0 $
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