1X/4x2=x-3

Solution for 1X/4x2=x-3 equation:

x in (-oo:+oo)

((1*X)/4)*x^2 = x-3 // - x-3

((1*X)/4)*x^2-x+3 = 0

(X/4)*x^2-x+3 = 0

1/4*X*x^2-x+3 = 0

DELTA = (-1)^2-(1/4*3*4*X)

DELTA = 1-3*X

1-3*X = 0

1-3*X = 0 // - 1

-3*X = -1 // : -3

X = -1/(-3)

X = 1/3

DELTA = 0  <=>  t_1 = 1/3

x = 1/(1/4*2*X) i X = 1/3

x = 2*X^-1 i X = 1/3

( x = ((1-3*X)^(1/2)+1)/(1/4*2*X) or x = (1-(1-3*X)^(1/2))/(1/4*2*X) ) i X > 1/3

( x = 2*X^-1*((1-3*X)^(1/2)+1) or x = 2*X^-1*(1-(1-3*X)^(1/2)) ) i X > 1/3

X-1/3 > 0

X-1/3 > 0 // + 1/3

X > 1/3

x in { 2*X^-1, 2*X^-1*((1-3*X)^(1/2)+1), 2*X^-1*(1-(1-3*X)^(1/2)) }