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1=6+z2
We move all terms to the left:
1-(6+z2)=0
We add all the numbers together, and all the variables
-(+z^2+6)+1=0
We get rid of parentheses
-z^2-6+1=0
We add all the numbers together, and all the variables
-1z^2-5=0
a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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