1=3(k-7)-5

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Solution for 1=3(k-7)-5 equation: 



1=3(k-7)-5

We move all terms to the left:

1-(3(k-7)-5)=0



We calculate terms in parentheses: -(3(k-7)-5), so:

3(k-7)-5

We multiply parentheses

3k-21-5

We add all the numbers together, and all the variables

3k-26

Back to the equation:

-(3k-26)



We get rid of parentheses

-3k+26+1=0

We add all the numbers together, and all the variables

-3k+27=0

We move all terms containing k to the left, all other terms to the right

-3k=-27

k=-27/-3

k=+9

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