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1=2560/d2
We move all terms to the left:
1-(2560/d2)=0
Domain of the equation: d2)!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
-(+2560/d2)+1=0
We get rid of parentheses
-2560/d2+1=0
We multiply all the terms by the denominator
1*d2-2560=0
We add all the numbers together, and all the variables
d^2-2560=0
a = 1; b = 0; c = -2560;
Δ = b2-4ac
Δ = 02-4·1·(-2560)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{10}}{2*1}=\frac{0-32\sqrt{10}}{2} =-\frac{32\sqrt{10}}{2} =-16\sqrt{10} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{10}}{2*1}=\frac{0+32\sqrt{10}}{2} =\frac{32\sqrt{10}}{2} =16\sqrt{10} $
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