1=2(t+13)/10+t

Solution for 1=2(t+13)/10+t equation:

1=2(t+13)/10+t

We move all terms to the left:

1-(2(t+13)/10+t)=0


Domain of the equation: 10+t)!=0

We move all terms containing t to the left, all other terms to the right

t)!=-10

t!=-10/1

t!=-10

t∈R


We multiply all the terms by the denominator


-(2(t+13)+1*10+t)=0


We calculate terms in parentheses: -(2(t+13)+1*10+t), so:

2(t+13)+1*10+t

determiningTheFunctionDomain
2(t+13)+t+1*10

We add all the numbers together, and all the variables

t+2(t+13)+10

We multiply parentheses

t+2t+26+10

We add all the numbers together, and all the variables

3t+36

Back to the equation:

-(3t+36)


We get rid of parentheses

-3t-36=0

We move all terms containing t to the left, all other terms to the right

-3t=36

t=36/-3

t=-12