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1=1/2(6q+8)-6
We move all terms to the left:
1-(1/2(6q+8)-6)=0
Domain of the equation: 2(6q+8)-6)!=0We multiply all the terms by the denominator
q∈R
-(1+1*2(6q+8)-6)=0
We calculate terms in parentheses: -(1+1*2(6q+8)-6), so:We add all the numbers together, and all the variables
1+1*2(6q+8)-6
determiningTheFunctionDomain 1*2(6q+8)+1-6
We add all the numbers together, and all the variables
1*2(6q+8)-5
Wy multiply elements
2q(6-5
Back to the equation:
-(2q(6-5)
-(2q1=0
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