1=-7y+2(y+8)

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Solution for 1=-7y+2(y+8) equation: 



1=-7y+2(y+8)

We move all terms to the left:

1-(-7y+2(y+8))=0



We calculate terms in parentheses: -(-7y+2(y+8)), so:

-7y+2(y+8)

We multiply parentheses

-7y+2y+16

We add all the numbers together, and all the variables

-5y+16

Back to the equation:

-(-5y+16)



We get rid of parentheses

5y-16+1=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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