1=-3(c-18)+-8

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Solution for 1=-3(c-18)+-8 equation: 



1=-3(c-18)+-8

We move all terms to the left:

1-(-3(c-18)+-8)=0

We use the square of the difference formula

-(-3(c-18)-8)+1=0



We calculate terms in parentheses: -(-3(c-18)-8), so:

-3(c-18)-8

We multiply parentheses

-3c+54-8

We add all the numbers together, and all the variables

-3c+46

Back to the equation:

-(-3c+46)



We get rid of parentheses

3c-46+1=0

We add all the numbers together, and all the variables

3c-45=0

We move all terms containing c to the left, all other terms to the right

3c=45

c=45/3

c=15

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