1=-2(1+3k)-3(k-1)

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Solution for 1=-2(1+3k)-3(k-1) equation: 



1=-2(1+3k)-3(k-1)

We move all terms to the left:

1-(-2(1+3k)-3(k-1))=0

We add all the numbers together, and all the variables

-(-2(3k+1)-3(k-1))+1=0



We calculate terms in parentheses: -(-2(3k+1)-3(k-1)), so:

-2(3k+1)-3(k-1)

We multiply parentheses

-6k-3k-2+3

We add all the numbers together, and all the variables

-9k+1

Back to the equation:

-(-9k+1)



We get rid of parentheses

9k-1+1=0

We add all the numbers together, and all the variables

9k=0

k=0/9

k=0

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