1=-(m+-8)+-8

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Solution for 1=-(m+-8)+-8 equation: 



1=-(m+-8)+-8

We move all terms to the left:

1-(-(m+-8)+-8)=0

We add all the numbers together, and all the variables

-(-(m-8)+-8)+1=0

We use the square of the difference formula

-(-(m-8)-8)+1=0



We calculate terms in parentheses: -(-(m-8)-8), so:

-(m-8)-8

We get rid of parentheses

-m+8-8

We add all the numbers together, and all the variables

-m

Back to the equation:

-(-m)



We add all the numbers together, and all the variables

-(-1m)+1=0

We get rid of parentheses

1m+1=0

We add all the numbers together, and all the variables

m+1=0

We move all terms containing m to the left, all other terms to the right

m=-1

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