1=(4x+3)+(x-8)

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Solution for 1=(4x+3)+(x-8) equation: 



1=(4x+3)+(x-8)

We move all terms to the left:

1-((4x+3)+(x-8))=0



We calculate terms in parentheses: -((4x+3)+(x-8)), so:

(4x+3)+(x-8)

We get rid of parentheses

4x+x+3-8

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

-5x+5+1=0

We add all the numbers together, and all the variables

-5x+6=0

We move all terms containing x to the left, all other terms to the right

-5x=-6

x=-6/-5

x=1+1/5

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