19x+32=3(4x+2)+7x+5

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Solution for 19x+32=3(4x+2)+7x+5 equation: 


Simplifying
19x + 32 = 3(4x + 2) + 7x + 5

Reorder the terms:
32 + 19x = 3(4x + 2) + 7x + 5

Reorder the terms:
32 + 19x = 3(2 + 4x) + 7x + 5
32 + 19x = (2 * 3 + 4x * 3) + 7x + 5
32 + 19x = (6 + 12x) + 7x + 5

Reorder the terms:
32 + 19x = 6 + 5 + 12x + 7x

Combine like terms: 6 + 5 = 11
32 + 19x = 11 + 12x + 7x

Combine like terms: 12x + 7x = 19x
32 + 19x = 11 + 19x

Add '-19x' to each side of the equation.
32 + 19x + -19x = 11 + 19x + -19x

Combine like terms: 19x + -19x = 0
32 + 0 = 11 + 19x + -19x
32 = 11 + 19x + -19x

Combine like terms: 19x + -19x = 0
32 = 11 + 0
32 = 11

Solving
32 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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