19x+2(x+1)=21(x+1)-19

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Solution for 19x+2(x+1)=21(x+1)-19 equation:


Simplifying
19x + 2(x + 1) = 21(x + 1) + -19

Reorder the terms:
19x + 2(1 + x) = 21(x + 1) + -19
19x + (1 * 2 + x * 2) = 21(x + 1) + -19
19x + (2 + 2x) = 21(x + 1) + -19

Reorder the terms:
2 + 19x + 2x = 21(x + 1) + -19

Combine like terms: 19x + 2x = 21x
2 + 21x = 21(x + 1) + -19

Reorder the terms:
2 + 21x = 21(1 + x) + -19
2 + 21x = (1 * 21 + x * 21) + -19
2 + 21x = (21 + 21x) + -19

Reorder the terms:
2 + 21x = 21 + -19 + 21x

Combine like terms: 21 + -19 = 2
2 + 21x = 2 + 21x

Add '-2' to each side of the equation.
2 + -2 + 21x = 2 + -2 + 21x

Combine like terms: 2 + -2 = 0
0 + 21x = 2 + -2 + 21x
21x = 2 + -2 + 21x

Combine like terms: 2 + -2 = 0
21x = 0 + 21x
21x = 21x

Add '-21x' to each side of the equation.
21x + -21x = 21x + -21x

Combine like terms: 21x + -21x = 0
0 = 21x + -21x

Combine like terms: 21x + -21x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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