19k=2(k+13)+3(8k+3)=1-6k+2+3k

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Solution for 19k=2(k+13)+3(8k+3)=1-6k+2+3k equation: 



19k=2(k+13)+3(8k+3)=1-6k+2+3k

We move all terms to the left:

19k-(2(k+13)+3(8k+3))=0



We calculate terms in parentheses: -(2(k+13)+3(8k+3)), so:

2(k+13)+3(8k+3)

We multiply parentheses

2k+24k+26+9

We add all the numbers together, and all the variables

26k+35

Back to the equation:

-(26k+35)



We get rid of parentheses

19k-26k-35=0

We add all the numbers together, and all the variables

-7k-35=0

We move all terms containing k to the left, all other terms to the right

-7k=35

k=35/-7

k=-5

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