19=3(6n-5)-7(n+3)

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Solution for 19=3(6n-5)-7(n+3) equation: 



19=3(6n-5)-7(n+3)

We move all terms to the left:

19-(3(6n-5)-7(n+3))=0



We calculate terms in parentheses: -(3(6n-5)-7(n+3)), so:

3(6n-5)-7(n+3)

We multiply parentheses

18n-7n-15-21

We add all the numbers together, and all the variables

11n-36

Back to the equation:

-(11n-36)



We get rid of parentheses

-11n+36+19=0

We add all the numbers together, and all the variables

-11n+55=0

We move all terms containing n to the left, all other terms to the right

-11n=-55

n=-55/-11

n=+5

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