19=2-(b+5)

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Solution for 19=2-(b+5) equation:



19=2-(b+5)
We move all terms to the left:
19-(2-(b+5))=0
We calculate terms in parentheses: -(2-(b+5)), so:
2-(b+5)
determiningTheFunctionDomain -(b+5)+2
We get rid of parentheses
-b-5+2
We add all the numbers together, and all the variables
-1b-3
Back to the equation:
-(-1b-3)
We get rid of parentheses
1b+3+19=0
We add all the numbers together, and all the variables
b+22=0
We move all terms containing b to the left, all other terms to the right
b=-22

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