192+(x)(x)=(16+x)(12+x)

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Solution for 192+(x)(x)=(16+x)(12+x) equation:


Simplifying
192 + (x)(x) = (16 + x)(12 + x)

Multiply x * x
192 + x2 = (16 + x)(12 + x)

Multiply (16 + x) * (12 + x)
192 + x2 = (16(12 + x) + x(12 + x))
192 + x2 = ((12 * 16 + x * 16) + x(12 + x))
192 + x2 = ((192 + 16x) + x(12 + x))
192 + x2 = (192 + 16x + (12 * x + x * x))
192 + x2 = (192 + 16x + (12x + x2))

Combine like terms: 16x + 12x = 28x
192 + x2 = (192 + 28x + x2)

Add '-192' to each side of the equation.
192 + -192 + x2 = 192 + 28x + -192 + x2

Combine like terms: 192 + -192 = 0
0 + x2 = 192 + 28x + -192 + x2
x2 = 192 + 28x + -192 + x2

Reorder the terms:
x2 = 192 + -192 + 28x + x2

Combine like terms: 192 + -192 = 0
x2 = 0 + 28x + x2
x2 = 28x + x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = 28x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 28x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 28x + 0
0 = 28x

Solving
0 = 28x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28x' to each side of the equation.
0 + -28x = 28x + -28x
Remove the zero:
-28x = 28x + -28x

Combine like terms: 28x + -28x = 0
-28x = 0

Divide each side by '-28'.
x = 0

Simplifying
x = 0

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