190=x(2x+4)*2

Solution for 190=x(2x+4)*2 equation:

190=x(2x+4)*2

We move all terms to the left:

190-(x(2x+4)*2)=0


We calculate terms in parentheses: -(x(2x+4)*2), so:

x(2x+4)*2

We multiply parentheses

4x^2+8x

Back to the equation:

-(4x^2+8x)


We get rid of parentheses

-4x^2-8x+190=0

a = -4; b = -8; c = +190;
Δ = b2-4ac
Δ = -82-4·(-4)·190
Δ = 3104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3104}=\sqrt{16*194}=\sqrt{16}*\sqrt{194}=4\sqrt{194}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{194}}{2*-4}=\frac{8-4\sqrt{194}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{194}}{2*-4}=\frac{8+4\sqrt{194}}{-8}
$