19/7y+3=28-6/7y

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Solution for 19/7y+3=28-6/7y equation: 



19/7y+3=28-6/7y

We move all terms to the left:

19/7y+3-(28-6/7y)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R





Domain of the equation: 7y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

19/7y-(-6/7y+28)+3=0

We get rid of parentheses

19/7y+6/7y-28+3=0

We multiply all the terms by the denominator


-28*7y+3*7y+19+6=0

We add all the numbers together, and all the variables

-28*7y+3*7y+25=0

Wy multiply elements

-196y+21y+25=0

We add all the numbers together, and all the variables

-175y+25=0

We move all terms containing y to the left, all other terms to the right

-175y=-25

y=-25/-175

y=1/7

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