19-9(4n+3)=6(7n+2)-28n

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Solution for 19-9(4n+3)=6(7n+2)-28n equation: 



19-9(4n+3)=6(7n+2)-28n

We move all terms to the left:

19-9(4n+3)-(6(7n+2)-28n)=0

We multiply parentheses

-36n-(6(7n+2)-28n)-27+19=0



We calculate terms in parentheses: -(6(7n+2)-28n), so:

6(7n+2)-28n

We add all the numbers together, and all the variables

-28n+6(7n+2)

We multiply parentheses

-28n+42n+12

We add all the numbers together, and all the variables

14n+12

Back to the equation:

-(14n+12)



We add all the numbers together, and all the variables

-36n-(14n+12)-8=0

We get rid of parentheses

-36n-14n-12-8=0

We add all the numbers together, and all the variables

-50n-20=0

We move all terms containing n to the left, all other terms to the right

-50n=20

n=20/-50

n=-2/5

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