19-3c2=-224

Solution for 19-3c2=-224 equation:

19-3c^2=-224

We move all terms to the left:

19-3c^2-(-224)=0

We add all the numbers together, and all the variables

-3c^2+243=0

a = -3; b = 0; c = +243;
Δ = b2-4ac
Δ = 02-4·(-3)·243
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*-3}=\frac{-54}{-6}
=+9
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*-3}=\frac{54}{-6}
=-9
$