19-2(3x-1)5=x+2

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Solution for 19-2(3x-1)5=x+2 equation: 



19-2(3x-1)5=x+2

We move all terms to the left:

19-2(3x-1)5-(x+2)=0

We multiply parentheses

-30x-(x+2)+10+19=0

We get rid of parentheses

-30x-x-2+10+19=0

We add all the numbers together, and all the variables

-31x+27=0

We move all terms containing x to the left, all other terms to the right

-31x=-27

x=-27/-31

x=27/31

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