19-(2u+3)=2(u+3)+u

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Solution for 19-(2u+3)=2(u+3)+u equation:


Simplifying
19 + -1(2u + 3) = 2(u + 3) + u

Reorder the terms:
19 + -1(3 + 2u) = 2(u + 3) + u
19 + (3 * -1 + 2u * -1) = 2(u + 3) + u
19 + (-3 + -2u) = 2(u + 3) + u

Combine like terms: 19 + -3 = 16
16 + -2u = 2(u + 3) + u

Reorder the terms:
16 + -2u = 2(3 + u) + u
16 + -2u = (3 * 2 + u * 2) + u
16 + -2u = (6 + 2u) + u

Combine like terms: 2u + u = 3u
16 + -2u = 6 + 3u

Solving
16 + -2u = 6 + 3u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-3u' to each side of the equation.
16 + -2u + -3u = 6 + 3u + -3u

Combine like terms: -2u + -3u = -5u
16 + -5u = 6 + 3u + -3u

Combine like terms: 3u + -3u = 0
16 + -5u = 6 + 0
16 + -5u = 6

Add '-16' to each side of the equation.
16 + -16 + -5u = 6 + -16

Combine like terms: 16 + -16 = 0
0 + -5u = 6 + -16
-5u = 6 + -16

Combine like terms: 6 + -16 = -10
-5u = -10

Divide each side by '-5'.
u = 2

Simplifying
u = 2

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