19-(2c+3)=2(c+3)

Solution for 19-(2c+3)=2(c+3) equation:

Simplifying
19 + -1(2c + 3) = 2(c + 3)

Reorder the terms:
19 + -1(3 + 2c) = 2(c + 3)
19 + (3 * -1 + 2c * -1) = 2(c + 3)
19 + (-3 + -2c) = 2(c + 3)

Combine like terms: 19 + -3 = 16
16 + -2c = 2(c + 3)

Reorder the terms:
16 + -2c = 2(3 + c)
16 + -2c = (3 * 2 + c * 2)
16 + -2c = (6 + 2c)

Solving
16 + -2c = 6 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
16 + -2c + -2c = 6 + 2c + -2c

Combine like terms: -2c + -2c = -4c
16 + -4c = 6 + 2c + -2c

Combine like terms: 2c + -2c = 0
16 + -4c = 6 + 0
16 + -4c = 6

Add '-16' to each side of the equation.
16 + -16 + -4c = 6 + -16

Combine like terms: 16 + -16 = 0
0 + -4c = 6 + -16
-4c = 6 + -16

Combine like terms: 6 + -16 = -10
-4c = -10

Divide each side by '-4'.
c = 2.5

Simplifying
c = 2.5