19+48=-4(-4z+2)-5

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Solution for 19+48=-4(-4z+2)-5 equation: 



19+48=-4(-4z+2)-5

We move all terms to the left:

19+48-(-4(-4z+2)-5)=0

We add all the numbers together, and all the variables

-(-4(-4z+2)-5)+67=0



We calculate terms in parentheses: -(-4(-4z+2)-5), so:

-4(-4z+2)-5

We multiply parentheses

16z-8-5

We add all the numbers together, and all the variables

16z-13

Back to the equation:

-(16z-13)



We get rid of parentheses

-16z+13+67=0

We add all the numbers together, and all the variables

-16z+80=0

We move all terms containing z to the left, all other terms to the right

-16z=-80

z=-80/-16

z=+5

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